CJ-19:Sorting array numbers in ascending order

Type the programs in NOTEPAD or DOS prompt itself, for Consol Application.
Type in NETBEANS or ECLIPSE for Window Application.
Here after , I am just typing the programs only..to know more about it , refer

Introduction to JAVA 

before doing any JAVA Programs.

***********************************************************************************************

import java.io.*;

public class ascending 

{

    public static void main(String args[])throws Exception

    {

        DataInputStream din=new DataInputStream(System.in);

        int t,i,j;

        int n=0;

        int result=0;

        int a[]=new int[10];

        System.out.println("Enter the limit :");

        n=Integer.parseInt(din.readLine());

        System.out.println("Enter the numbers :");

        for(i=0;i<n;i++)

        {

            a[i]=Integer.parseInt(din.readLine());

        }

        for(i=0;i<n;i++)

        {

            for(j=0;j<n;j++)

            {

                if(a[i]<a[j])

                {

                    t=a[i];

                    a[i]=a[j];

                    a[j]=t;

                }

            }

        }

        System.out.println("The numbers in ascending orer is :");

        for(i=0;i<n;i++)

            System.out.println(a[i]);   

    }   

}

=========================================================================
Output : 

Enter the limit :

3

Enter the numbers :

5

7

2

The numbers in ascending order is :

2

5

7

CJ-16 : Numbers divisible by 7, and its sum(2)

Type the programs in NOTEPAD or DOS prompt itself, for Consol Application.
Type in NETBEANS or ECLIPSE for Window Application.
Here after , I am just typing the programs only..to know more about it , refer

Introduction to JAVA 

before doing any JAVA Programs.

***********************************************************************************************

import java.io.*;

public class div1
{
    public static void main(String args[])
    {
        int sum=0,ct=0,n,i;
        try
        {
            DataInputStream s= new DataInputStream(System.in);
            System.out.println("Enter the limit :");
            n=Integer.parseInt(s.readLine());
            System.out.println("Numbers divisible by 7 are :");
            for(i=0;i<n;i++)
            {
                if(i%7==0)
                {
                    System.out.println(i);
                    ct++;
                    sum=sum+i;
                }
            }
            System.out.println("Sum= "+sum);
            System.out.println("Total Numbers divisible by 7 is :"+ct);
        }
        catch(Exception e)
        {
        }
    }
}
=========================================================================
Output :

Enter the limit :

50

Numbers divisible by 7 are :

0
7
14
21
28
35
42
49
Sum= 196
Total Numbers divisible by 7 is :8

CJ-15:Numbers divisible by 7, and its sum(1)

Type the programs in NOTEPAD or DOS prompt itself, for Consol Application.
Type in NETBEANS or ECLIPSE for Window Application.
Here after , I am just typing the programs only..to know more about it , refer

Introduction to JAVA 

before doing any JAVA Programs.

***********************************************************************************************

import java.io.*;
class div
{
public static void main(String args[])
{
   int sum=0,ct=0,n,i=0;
   try
   {
DataInputStream s=new DataInputStream(System.in);
System.out.println("Enter Limit :");
n=Integer.parseInt(s.readLine());
System.out.println("Numbers divisible by 7 are :");
do
{
   if(i%7==0)
   {
System.out.println(i);
ct++;
sum=sum+i;
   }
   i++;
}
while(i<=n);
System.out.println("Sum = "+sum);
System.out.println("Total Numbers divisible by 7 is : "+ct);
    }
    catch(Exception e)
    {
    }
}
}   

=========================================================================

Output :

Enter Limit:

50

Numbers divisible by 7 are :

0

7

14

21

28

35

42

49
Sum = 196

Total Numbers divisible by 7 is : 8