C-44 : Check your Progress -1

Refer Sum of 1 to 100 numbers


1 : State the output of the below given programs :



 (a)

##include<stdio.h> #include<conio.h> void main()             {             clrscr();             int j=5;             for (printf("Will this loop be entered\n");j<2;j=1)             printf("Print this,if the loop is entered...");             printf("Was the loop entered\n");             getch();             }

Answer :
Will this loop be entered
Was the loop entered
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 (b)

#include<stdio.h> #include<conio.h> void main()             {             clrscr();             int j=5;             for (printf("Will this loop be entered\n");j<6;j=7)             printf("Print this,if the loop is entered...j=%d\n",j);             printf("Is the Boolean j 6 still true?\n%s",j<6?"Yes,":"No,");             printf("Because j is now %d\n",j);             getch();             }

Answer :
Will this loop be entered
Print this,if the loop is entered...j=5
Is the Boolean j 6 still true?
No,Because j is now 7
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 (c)

#include<stdio.h> #include<conio.h> void main()             {             clrscr();             int j;             for(j=0;j<2;j++)               {               printf("The for(;;)loop is really quite easy to use.\n");               printf("I\'ve said this %s.\n",j==0?"once":"twice");               }             printf("What I say %d times must be true!\n",j);             getch();             }

Answer :
The for(;;)loop is really quite easy to use.
\'ve said this once
The for(;;)loop is really quite easy to use.
\'ve said this twice
What I say 2 times must be true!
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2 : Replace the for(;;) statement in the program 1(a) above by :


for (i=1;sum=0;i<101;i++)
Realize that the comma operator can be used with the expressions controlling a for(;;) statement. That in fact is its most common usage.


Observe that the value of the loop index is retained on exit from the loop.

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3 : In Program 1(c) above, can the && operator be replaced by the || operator ?
Can it be replaced by the comma operator ?
Are the parentheses around sum+=i++ required ?


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4 :



(Will continue...)


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