C-44 : Check your Progress -1

Refer Sum of 1 to 100 numbers


1 : State the output of the below given programs :



 (a)

##include<stdio.h> #include<conio.h> void main()             {             clrscr();             int j=5;             for (printf("Will this loop be entered\n");j<2;j=1)             printf("Print this,if the loop is entered...");             printf("Was the loop entered\n");             getch();             }

Answer :
Will this loop be entered
Was the loop entered
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 (b)

#include<stdio.h> #include<conio.h> void main()             {             clrscr();             int j=5;             for (printf("Will this loop be entered\n");j<6;j=7)             printf("Print this,if the loop is entered...j=%d\n",j);             printf("Is the Boolean j 6 still true?\n%s",j<6?"Yes,":"No,");             printf("Because j is now %d\n",j);             getch();             }

Answer :
Will this loop be entered
Print this,if the loop is entered...j=5
Is the Boolean j 6 still true?
No,Because j is now 7
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 (c)

#include<stdio.h> #include<conio.h> void main()             {             clrscr();             int j;             for(j=0;j<2;j++)               {               printf("The for(;;)loop is really quite easy to use.\n");               printf("I\'ve said this %s.\n",j==0?"once":"twice");               }             printf("What I say %d times must be true!\n",j);             getch();             }

Answer :
The for(;;)loop is really quite easy to use.
\'ve said this once
The for(;;)loop is really quite easy to use.
\'ve said this twice
What I say 2 times must be true!
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2 : Replace the for(;;) statement in the program 1(a) above by :


for (i=1;sum=0;i<101;i++)
Realize that the comma operator can be used with the expressions controlling a for(;;) statement. That in fact is its most common usage.


Observe that the value of the loop index is retained on exit from the loop.

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3 : In Program 1(c) above, can the && operator be replaced by the || operator ?
Can it be replaced by the comma operator ?
Are the parentheses around sum+=i++ required ?


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4 :



(Will continue...)


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C-43 : Sum of 1 to 100 numbers

Refer  Find Sum , Sum of n even numbers using user defined fun... 


1st Method :

#include<stdio.h> #include<conio.h> void main()             {             clrscr();             int i,sum=0;             for(i=1;i<101;i++)                         sum=sum+i;             printf("The sum of the numbers from 1 to %d is %d\n",i-1,sum);             getch();             }

2nd Method :

#include<stdio.h> #include<conio.h> void main()             {             clrscr();             int i,sum=0;             for(i=1;i<101;sum+=i++)             ;             printf("The sum of the numbers from 1 to %d is %d\n",i-1,sum);             getch();             }

3rd Method :

#include<stdio.h> #include<conio.h> void main()             {             clrscr();             int i,sum=0;             for(i=1;i<101 && (sum+=i++);)             ;             printf("The sum of the numbers from 1 to %d is %d\n",i-1,sum);             getch();             }

Output : 


The sum of the numbers from 1 to 100 is 5050
=================================================================

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C-42 : Read values from keyboard for calculations

Read values from keyboard for calculations . And see how scanf() works.

Refer Simple Calculations also.

#include<stdio.h> #include<conio.h> main()      {       clrscr();       int x,y,z;       printf("Enter a value of x:");       scanf("%d",&x);       printf("Enter a value for y:");       scanf("%d",&y);       z=x*y;       printf("z=x*y=%d\n",z);       getch();       return 0;      }

Output :

Enter a value of x: 3Enter a value of y: 4
z=x*y=12
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C-41: Simple Calculations

Elementary operations with small integers:

Refer Find Sum also.

#include<stdio.h> #include<conio.h> main()       {       clrscr();       printf("\n\t\n\t");       printf("x=%d,y=%d\n",x,y);       z=x-y;       printf("z=x-y=%d\n",z);       z=x*y;       printf("z=x*y=%d\n",z);       z=x/y;       printf("z=x/y=%d\n",z);       z=y/x;       printf("z=y/x=%d\n",z);       z=x%y;       printf("z=x%%y=%d\n",z);       z=y%x;       printf("z=y%%x=%d\n",z);       getch();       }

Output :x=5,y=7
z=x-y=-2
z=x*y=35
z=x/y=0
z=y/x=1
z=x%y=5
z=y%x=2
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C-40 : Check your Progress -1

Refer

1.  My first C Program 
2.  Example for Nested IF
3. Example of Escape Sequence (\n)

Then , try to answer the following questions :

1. Do you think comments can be nested , that is , can you have a comment with in a comment? Write a program with a nested comment and see if you can compile it.
2. Write a C language program that gives for its output :    \* This is a C Comment*\
3. Debug the following program :

#include<stdio.h>
#include<conio.h>
void main{}
(
            print("print this\m"\*very easy*\).
)

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(Please use Comment section to post your answer).
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