C-44 : Check your Progress -1

Refer Sum of 1 to 100 numbers


1 : State the output of the below given programs :



 (a)

##include<stdio.h> #include<conio.h> void main()             {             clrscr();             int j=5;             for (printf("Will this loop be entered\n");j<2;j=1)             printf("Print this,if the loop is entered...");             printf("Was the loop entered\n");             getch();             }

Answer :
Will this loop be entered
Was the loop entered
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 (b)

#include<stdio.h> #include<conio.h> void main()             {             clrscr();             int j=5;             for (printf("Will this loop be entered\n");j<6;j=7)             printf("Print this,if the loop is entered...j=%d\n",j);             printf("Is the Boolean j 6 still true?\n%s",j<6?"Yes,":"No,");             printf("Because j is now %d\n",j);             getch();             }

Answer :
Will this loop be entered
Print this,if the loop is entered...j=5
Is the Boolean j 6 still true?
No,Because j is now 7
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 (c)

#include<stdio.h> #include<conio.h> void main()             {             clrscr();             int j;             for(j=0;j<2;j++)               {               printf("The for(;;)loop is really quite easy to use.\n");               printf("I\'ve said this %s.\n",j==0?"once":"twice");               }             printf("What I say %d times must be true!\n",j);             getch();             }

Answer :
The for(;;)loop is really quite easy to use.
\'ve said this once
The for(;;)loop is really quite easy to use.
\'ve said this twice
What I say 2 times must be true!
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2 : Replace the for(;;) statement in the program 1(a) above by :


for (i=1;sum=0;i<101;i++)
Realize that the comma operator can be used with the expressions controlling a for(;;) statement. That in fact is its most common usage.


Observe that the value of the loop index is retained on exit from the loop.

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3 : In Program 1(c) above, can the && operator be replaced by the || operator ?
Can it be replaced by the comma operator ?
Are the parentheses around sum+=i++ required ?


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4 :



(Will continue...)


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C-43 : Sum of 1 to 100 numbers

Refer  Find Sum , Sum of n even numbers using user defined fun... 


1st Method :

#include<stdio.h> #include<conio.h> void main()             {             clrscr();             int i,sum=0;             for(i=1;i<101;i++)                         sum=sum+i;             printf("The sum of the numbers from 1 to %d is %d\n",i-1,sum);             getch();             }

2nd Method :

#include<stdio.h> #include<conio.h> void main()             {             clrscr();             int i,sum=0;             for(i=1;i<101;sum+=i++)             ;             printf("The sum of the numbers from 1 to %d is %d\n",i-1,sum);             getch();             }

3rd Method :

#include<stdio.h> #include<conio.h> void main()             {             clrscr();             int i,sum=0;             for(i=1;i<101 && (sum+=i++);)             ;             printf("The sum of the numbers from 1 to %d is %d\n",i-1,sum);             getch();             }

Output : 


The sum of the numbers from 1 to 100 is 5050
=================================================================

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C-42 : Read values from keyboard for calculations

Read values from keyboard for calculations . And see how scanf() works.

Refer Simple Calculations also.

#include<stdio.h> #include<conio.h> main()      {       clrscr();       int x,y,z;       printf("Enter a value of x:");       scanf("%d",&x);       printf("Enter a value for y:");       scanf("%d",&y);       z=x*y;       printf("z=x*y=%d\n",z);       getch();       return 0;      }

Output :

Enter a value of x: 3Enter a value of y: 4
z=x*y=12
=========================================================================
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C-41: Simple Calculations

Elementary operations with small integers:

Refer Find Sum also.

#include<stdio.h> #include<conio.h> main()       {       clrscr();       printf("\n\t\n\t");       printf("x=%d,y=%d\n",x,y);       z=x-y;       printf("z=x-y=%d\n",z);       z=x*y;       printf("z=x*y=%d\n",z);       z=x/y;       printf("z=x/y=%d\n",z);       z=y/x;       printf("z=y/x=%d\n",z);       z=x%y;       printf("z=x%%y=%d\n",z);       z=y%x;       printf("z=y%%x=%d\n",z);       getch();       }

Output :x=5,y=7
z=x-y=-2
z=x*y=35
z=x/y=0
z=y/x=1
z=x%y=5
z=y%x=2
=========================================================================
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C-40 : Check your Progress -1

Refer

1.  My first C Program 
2.  Example for Nested IF
3. Example of Escape Sequence (\n)

Then , try to answer the following questions :

1. Do you think comments can be nested , that is , can you have a comment with in a comment? Write a program with a nested comment and see if you can compile it.
2. Write a C language program that gives for its output :    \* This is a C Comment*\
3. Debug the following program :

#include<stdio.h>
#include<conio.h>
void main{}
(
            print("print this\m"\*very easy*\).
)

========================================================================
(Please use Comment section to post your answer).
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C-39 : Example of Escape Sequence (\n)

\n is the example of  Escape Sequence.
It's used to print the newline character.
Note that ,\n doesn't appear in the output.
Place \n wherever you want to insert a new line in the output.

See the examples below :
(Eg:-1) :

#include<stdio.h> #include<conio.h> void main() {             clrscr();             printf("This\nString\nwill\nbe\nprinted\nin\n8\nlines.\n");             getch(); }

Output:
This
String
will
be
printed
in
8
lines
===========================================================================
(Eg :-2) :

#include<stdio.h> #include<conio.h> main()             {             clrscr();             printf("This is the First Line of Output.");             printf("But is this the Second\nline of Output?");             getch();             }

Output:
This is the First Line of Output. But is this the Second
line of Output?


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(Eg :-3) : 

#include<stdio.h> #include<conio.h> main()             {             clrscr();             printf("In how many lines will the output\nof this program be printed?");             getch();             }

Output:
In how many lines will the output
of this program be printed?
===========================================================================
(Eg:-4) :


What will be the output of the program ?

#include<stdio.h> #include<conio.h> main()       {       clrscr();       printf("\"\\n\", the teacher said,\"is used to  ");       printf("insert a new line in a C string.\"");       printf("\n\" I C,I C\",said the blind student.\n");       getch();       return 0;       }

Output:


" \n", the teacher said, "is used to  insert a new line in a C string".
"I C,I C", said the blind student.

(An important point to remember :  ""(Double Quote) character is not an Escape Sequence ).
.


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